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GCSE Mathematics 02 — Algebra

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Topics include Algebraic Foundations & Substitution, Laws of Indices, Solving Linear Equations, Rearranging Formulae & Applied Algebra, Expanding & Factorising Polynomials, Solving Quadratics, Algebraic Fractions, and Surds.

Mathematics EN
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Laws of Indices

Rules for simplifying terms involving powers, including negative, zero, and fractional indices.

Key points

  • Multiplication: am×an=am+na^m \times a^n = a^{m+n}. Add the powers.
  • Division: am÷an=amna^m \div a^n = a^{m-n}. Subtract the powers.
  • Power of a Power: (am)n=am×n(a^m)^n = a^{m \times n}. Multiply the powers.
  • Zero Index: a0=1a^0 = 1 (for ae0a e 0).
  • Negative Index: an=1ana^{-n} = \frac{1}{a^n}. It represents the reciprocal.

Worked example

Question

Simplify (8x627)23\left(\frac{8x^6}{27}\right)^{-\frac{2}{3}}.

Solution

1. Handle the negative power by flipping the fraction: (278x6)23\left(\frac{27}{8x^6}\right)^{\frac{2}{3}}.
2. Apply the fractional power (cube root then square).
3. Cube root: 273=3\sqrt[3]{27} = 3, 83=2\sqrt[3]{8} = 2, x63=x2\sqrt[3]{x^6} = x^2. Fraction becomes 32x2\frac{3}{2x^2}.
4. Square everything: 32(2x2)2=94x4\frac{3^2}{(2x^2)^2} = \frac{9}{4x^4}.

Common pitfalls

  • Multiplying bases instead of indices in (x2)3(x^2)^3 (getting x5x^5 instead of x6x^6).
  • Thinking x0=0x^0 = 0.
  • Applying the power to the algebra but forgetting the coefficient (e.g., (2x)3=2x3(2x)^3 = 2x^3 instead of 8x38x^3).

Prerequisites

  • Square and cube numbers
  • Basic arithmetic with fractions
Further resources
  • Index Laws

    Comprehensive guide to all index laws.

    Maths Genie · article