AS & A-Level Chemistry 12 — Thermodynamics and electrochemistry
PublicIndependent Deckloop A Level Chemistry study material aligned with Cambridge International 9701 (2025–2027). Deck 12 of 18: Thermodynamics and electrochemistry. Original explanations, worked applications and practice. Not affiliated with or endorsed by Cambridge International Education.
Chemistry
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A-Level
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Lattice Energy and Electron Affinity
Thermochemistry extends to ionic lattices using theoretical energy cycles. The standard enthalpy change of atomisation, , is the enthalpy change when one mole of gaseous atoms is formed from the element in its standard state. The first electron affinity is the enthalpy change when one mole of electrons is added to one mole of gaseous atoms to form one mole of gaseous 1- ions. Lattice energy, , is defined by Cambridge as the enthalpy change when one mole of an ionic solid is formed from its gaseous ions; it is inherently an exothermic quantity. A Born-Haber cycle applies Hess's Law to link the standard enthalpy change of formation of an ionic compound to its constituent atomisation enthalpies, ionisation energies, electron affinities, and lattice energy. Electron affinity is influenced by nuclear charge, atomic radius, and shielding. Down Groups 16 and 17, first electron affinity generally becomes less exothermic due to increasing atomic radius and shielding, which outweigh the increased nuclear charge. However, the first electron affinities of oxygen and fluorine are anomalously less exothermic than those of sulfur and chlorine. Their small atomic radii lead to significant electron-electron repulsion in the compact subshell, making the addition of an incoming electron less energetically favourable.
Key points
- Enthalpy of atomisation forms exactly one mole of gaseous atoms from the standard state.
- First electron affinity forms one mole of gaseous 1- ions from gaseous atoms and is typically exothermic.
- Cambridge lattice energy refers to the formation of a solid lattice from gaseous ions, so it is always negative (exothermic).
- Down Groups 16 and 17, atomic radius and shielding increase, making electron affinity less exothermic.
- Fluorine and oxygen have less exothermic first electron affinities than expected due to severe electron-electron repulsion in their small subshells.
Worked example
Question
Construct a balanced equation, including state symbols, for the standard enthalpy change of atomisation of bromine, and explain why its value differs from the bond dissociation enthalpy of the bond.
Solution
1. Identify the standard state of bromine at , which is a liquid, .
2. By definition, atomisation must form exactly one mole of gaseous atoms.
3. Write the balanced equation: .
4. Bond dissociation enthalpy refers to breaking one mole of bonds in the gaseous state: .
The atomisation equation is . At the stated temperature, the enthalpy is half the molar enthalpy of vaporisation of plus half its molar bond dissociation enthalpy: . Both factors of one half are needed because only half a mole of produces one mole of atoms.
2. By definition, atomisation must form exactly one mole of gaseous atoms.
3. Write the balanced equation: .
4. Bond dissociation enthalpy refers to breaking one mole of bonds in the gaseous state: .
The atomisation equation is . At the stated temperature, the enthalpy is half the molar enthalpy of vaporisation of plus half its molar bond dissociation enthalpy: . Both factors of one half are needed because only half a mole of produces one mole of atoms.
Common pitfalls
- Assuming the first electron affinity of fluorine is the most exothermic in Group 17; it is less exothermic than chlorine due to greater inter-electronic repulsion.
- Forgetting that atomisation forms exactly one mole of gaseous atoms, which often requires fractional stoichiometric coefficients for diatomic elements.
Prerequisites
- Study Bonding, shape and states of matter first.
- Study Enthalpy, chemical energy and redox first.
- Study Equilibria, acids and reaction rates first.